T H E E L E M E N T S |
Book I Proposition 4 | |
Let ABC, DEF be two triangles having the two sides AB, AC equal to the two sides DE, DF respectively, namely
AB to DE and
AC to DF, and
the angle BAC equal to the angle EDF. I say that the base BC is also equal to the base EF, the triangle ABC will be equal to the triangle DEF, and the remaining angles will be equal to the remaining angles respectively, namely those which the equal sides subtend, that is, the angle ABC to the angle DEF, and the angle ACB to the angle DFE. |
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